Fibbinary numbers: if n = F(i1) + F(i2) + ... + F(ik) is the Zeckendorf representation of n (i.e., write n in Fibonacci number system) then a(n) = 2^(i1 - 2) + 2^(i2 - 2) + ... + 2^(ik - 2). Also numbers whose binary representation contains no two adjacent 1's

Open in the 3-D viewerA003714 on the OEIS
| Terms | 100,000 (n = 0 … 99,999) |
|---|---|
| Decomposable (a > 2d) | 99,976 |
| Level class, k > L | 10,351 · 10.35 % |
| Weight class, k ≤ L | 89,625 · 89.65 % |
| Ties, k = L | 1 |
| On the level line L = 1 | 5,372 |
| Forced level, l ≤ d² | 241 |
| Range of a(n) | 0 … 9,704,020 |
| Range of the jump d | 1 … 2,796,203 |
| Largest weight k, level L | 9,703,763, 4,852,008 |
No two adjacent 1 bits in binary. The decomposition fails 24 times, each where the sequence jumps to the next power of two (a(n+1) >= 1.5 a(n)). Gap 1 carries 62 % of the terms and the level share is 10.35 %.
The decomposition
Every term of a strictly increasing sequence is written a(n) = k(n)·L(n) + d(n): the jump d = a(n+1) − a(n), the weight k the least divisor of a − d greater than d, the level L = (a − d)/k. A term decomposes when a > 2d; it is in the level class when k > L and in the weight class when k ≤ L. See decompwlj.com and arXiv:0711.0865, or how it works, with worked examples and a live one.