Centered square numbers: a(n) = 2*n*(n+1)+1. Sums of two consecutive squares. Also, consider all Pythagorean triples (X, Y, Z=Y+1) ordered by increasing Z; then sequence gives Z values

Open in the 3-D viewerA001844 on the OEIS
| Terms | 100,000 (n = 0 … 99,999) |
|---|---|
| Decomposable (a > 2d) | 99,996 |
| Level class, k > L | 99,996 · 100.00 % |
| Weight class, k ≤ L | 0 · 0.00 % |
| Ties, k = L | 0 |
| On the level line L = 1 | 8,412 |
| Forced level, l ≤ d² | 99,996 |
| Range of a(n) | 1 … 19,999,800,001 |
| Range of the jump d | 4 … 400,000 |
| Largest weight k, level L | 19,997,800,057, 49,609 |
2n(n + 1) + 1 = n^2 + (n + 1)^2. d = 4(n + 1) and a ~ 2 n^2 < d^2: forced level at every decomposable term (100 %). Every l is odd and the fullest line is L = 3 (10.9 %), ahead of L = 1 (8.4 %).
The decomposition
Every term of a strictly increasing sequence is written a(n) = k(n)·L(n) + d(n): the jump d = a(n+1) − a(n), the weight k the least divisor of a − d greater than d, the level L = (a − d)/k. A term decomposes when a > 2d; it is in the level class when k > L and in the weight class when k ≤ L. See decompwlj.com and arXiv:0711.0865, or how it works, with worked examples and a live one.